- Volume of sodium hydroxide solution = 25.00 ÷ 1000 = 0.0250 dm
^{3} - Amount of sodium hydroxide = 0.200 × 0.0250 = 0.005 mol.
- From the equation, 0.005 mol of NaOH reacts with 0.005 mol of HCl.
- Volume of hydrochloric acid = 22.70 ÷ 1000 = 0.0227 dm
^{3} - Concentration of hydrochloric acid = 0.005 mol ÷ 0.0227.
- = 0.220 mol/dm
^{3}

## How do you find the volume of acid in a titration?

Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the **acid x volume (V) of the acid = molarity (M) of the base x volume (V)** of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)

## How do you calculate the molarity of HCl from titration with NaOH?

First determine the moles of NaOH in the reaction. From the mole ratio, calculate the moles of H2SO4 that reacted. Finally, **divide the moles of H2SO4 by its volume** to get the molarity.

## What is the volume of HCl?

Concentrated hydrochloric acid has concentration of 12.19 mol/litre, The molar mass of HCl is 36.458 g/mol. 125 g is therefore (125/36.458) = 3.4286 moles. So the volume that would contain this number of moles is going to be (3.4286 / 12.19) = 0.28126 litres or **281.26 ml**.

## How do you find the concentration of a solution in a titration?

Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the **number of moles of solute per litre of solution**.)

## How do you make 1 mol of HCl?

To make 1 L of 1 mol/L HCl, you take **88 mL** of the concentrated solution and add water to make a total of 1 L.

## What volume of NaOH is required to neutralize the HCl?

Therefore, we will need **about 2.5 L** of sodium hydroxide to neutralize the hydrochloric acid.

## What is the formula of volume?

Table 3. Volume Formulas | ||
---|---|---|

Shape | Formula | Variables |

Cube | V=s3 | s is the length of the side. |

Right Rectangular Prism | V=LWH |
L is the length, W is the width and H is the height. |

Prism or Cylinder | V=Ah | A is the area of the base, h is the height. |

## What is the volume of HCl density?

Reagent | Density (g/mL) |
---|---|

HCl | 1.18 |

HNO3 | 1.41 |

H2SO4 | 1.84 |

CH3CO2H | 1.06 |

## How do you make 0.1 N HCl?

37 ml of solute/100 ml of solution. Therefore **add 8.3 ml of 37% HCL to 1 liter of D5W or NS** to create a 0.1N HCL solution.

## How do you find the average volume in a titration?

The volume of acid added is the final volume minus the start volume. To find the average titre (titration volume) **the values are added together and divided by the number of readings that were taken.**

## What is the concentration of unknown HCl solution?

Thus, concentration of the unknown HCl solution is **0.088 M**.

## How do you find the concentration of a solution in mol dm 3?

Concentration is measured in moles per cubic decimetre: mol dm–3. To find the concentration of a solution, **divide the number of moles by the volume in dm3**. If the volume is in cm3, divide the volume by 1000 first to convert it into dm3.

## What is the mass of 1 mol of HCl?

The molar mass of HCl is **36.46⋅g⋅mol−1** .

## How do you make a 2M solution of HCl?

- 1M HCl: add 1mol/12M = 83 ml conc. HCl to 1L of water or 8.3ml to 100ml.
- 2M HCl: add 2mol/12M = 167 ml conc. HCl to 1L of water or 16.7ml to 100ml.

## How do you make a standard solution of HCl?

**Add 8.26 mL of concentrated HCl to** about 50 mL of distilled water, stir, then add water up to 100 mL. Mass percent solutions are defined based on the grams of solute per 100 grams of solution.